(3x+5)(5x^2-19x+12)=0

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Solution for (3x+5)(5x^2-19x+12)=0 equation: 


Simplifying
(3x + 5)(5x2 + -19x + 12) = 0

Reorder the terms:
(5 + 3x)(5x2 + -19x + 12) = 0

Reorder the terms:
(5 + 3x)(12 + -19x + 5x2) = 0

Multiply (5 + 3x) * (12 + -19x + 5x2)
(5(12 + -19x + 5x2) + 3x * (12 + -19x + 5x2)) = 0
((12 * 5 + -19x * 5 + 5x2 * 5) + 3x * (12 + -19x + 5x2)) = 0
((60 + -95x + 25x2) + 3x * (12 + -19x + 5x2)) = 0
(60 + -95x + 25x2 + (12 * 3x + -19x * 3x + 5x2 * 3x)) = 0
(60 + -95x + 25x2 + (36x + -57x2 + 15x3)) = 0

Reorder the terms:
(60 + -95x + 36x + 25x2 + -57x2 + 15x3) = 0

Combine like terms: -95x + 36x = -59x
(60 + -59x + 25x2 + -57x2 + 15x3) = 0

Combine like terms: 25x2 + -57x2 = -32x2
(60 + -59x + -32x2 + 15x3) = 0

Solving
60 + -59x + -32x2 + 15x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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